for-loops solution for n sales

for-loops
Lothar Buchholz 4 years ago
parent 30543abaf9
commit e271940ba9

@ -1,20 +1,56 @@
import java.util.*;
import java.io.*;
import java.math.*;
import java.util.stream.IntStream;
/**
* Template code to help you parse the standard input
* according to the problem statement.
**/
class Solution {
public static void main( String[] args ) {
Scanner in = new Scanner( System.in );
// read values with in.next...() methods
// code your solution here
var scanner = new Scanner( System.in );
var sellCount = scanner.nextInt();
var prices = scanner.tokens()
.mapToInt( Integer::valueOf )
.toArray();
// Write result with System.out.println()
System.out.println( "value" );
System.out.println( maxProfits( sellCount, prices ));
}
// code your solution here
// 0 - 1 | ... | x-sellCount - x --> 0 - x-1 | ... | x-1 - x
private static int maxProfits( int sellCount, int[] prices ) {
var maxProfit = 0;
for ( int sale = 0; sale < sellCount; sale++ ) {
int max = 0;
// recursion end condition
if ( sellCount == 1 ) {
max = maxProfit( prices );
}
else {
for ( int index = 2; index < prices.length; index++ ) {
var firstRange = Arrays.copyOfRange( prices, 0, index );
final int max1 = maxProfit( firstRange );
var secondRange = Arrays.copyOfRange( prices, index, prices.length );
// reduce range sizes recursively
final int max2 = maxProfits( sellCount - 1, secondRange );
max = Math.max( max, max1 + max2 );
}
}
maxProfit = Math.max( maxProfit, max );
}
return maxProfit;
}
private static int maxProfit( int[] prices ) {
var maxProfit = 0;
for ( int index = 0; index < prices.length; index++ ) {
var range = Arrays.copyOfRange( prices, Math.min( index + 1, prices.length - 1 ), prices.length );
int max = IntStream.of( range ).max().orElse( 0 );
// difference between current price and future maximum
maxProfit = Math.max( maxProfit, max - prices[index] );
}
return maxProfit;
}
}

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