using real Iterator<Integer> instead of fake CharacterIterator

src/main/java/Solution.java

@@ -1,20 +1,35 @@
 import java.util.*;
-import java.io.*;
-import java.math.*;
+import java.util.function.BiPredicate;
 
-/**
- * Template code to help you parse the standard input 
- * according to the problem statement.
- **/
 class Solution {
     
-	public static void main( String[] args ) {
-		Scanner in = new Scanner( System.in );
-		// read values with in.next...() methods
+    // best readable version, also without dark ASCII code tricks
+    private static final BiPredicate<Integer, Integer> BRACKETS_MATCH = ( c1, c2 ) -> ( c1 != null && c2 != null )
+            && (( c1 == '(' && c2 == ')' ) || ( c1 == '[' && c2 == ']' ) || ( c1 == '{' && c2 == '}' ));
     
     // code your solution here
+    private static boolean checkNextChar( Deque<Integer> stack, Iterator<Integer> iter ) {
+        if ( ! iter.hasNext() ) return stack.isEmpty();
+        
+        int c = iter.next();
+        if ( BRACKETS_MATCH.test( stack.peek(), c )) {
+            stack.pop();
+        }
+        else {
+            stack.push( c );
+        }
+        
+        return checkNextChar( stack, iter );
+    }
+    
+    public static void main( String[] args ) {
+        // hint: read values via Scanner methods
+        var inputLine = new Scanner( System.in ).nextLine();
+        
+        var stack = new ArrayDeque<Integer>( inputLine.length() );
+        var iter  = inputLine.chars().iterator();
         
         // Write result with System.out.println()
-		System.out.println( "value" );
+        System.out.println( checkNextChar( stack, iter ) );
     }
 }