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recursive-
Author | SHA1 | Date |
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Lothar Buchholz | cd9a9e3936 | 5 years ago |
@ -1,42 +1,35 @@
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import java.util.*;
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import java.util.function.BiPredicate;
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/**
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* Template code to help you parse the standard input
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* according to the problem statement.
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**/
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class Solution {
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public static void main( String[] args ) {
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Scanner in = new Scanner( System.in );
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// read values with in.next...() methods
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String input = in.nextLine();
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// code your solution here
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boolean output = isInputWellFormed(input);
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// Write result with System.out.println()
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System.out.println( output );
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}
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private static boolean isInputWellFormed(String input) {
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HashMap<Character, Character> validPairs = new HashMap<>();
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validPairs.put('{', '}');
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validPairs.put('(', ')');
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validPairs.put('[', ']');
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Deque<Character> unmatchedChars = new ArrayDeque<>();
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for (int i = 0; i < input.length(); i++) {
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char currentChar = input.charAt(i);
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if (validPairs.keySet().contains(currentChar)) {
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unmatchedChars.push(currentChar); // Add only opening ({[ to the unmatchedChars.
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} else if (validPairs.values().contains(currentChar)) {
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if (!unmatchedChars.isEmpty() && validPairs.get(unmatchedChars.peekFirst()) == currentChar) {
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unmatchedChars.pop(); // Match found, empty the unmatchedChars.
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} else {
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return false;
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}
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}
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}
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return unmatchedChars.isEmpty();
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}
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// best readable version, also without dark ASCII code tricks
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private static final BiPredicate<Integer, Integer> BRACKETS_MATCH = ( c1, c2 ) -> ( c1 != null && c2 != null )
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&& (( c1 == '(' && c2 == ')' ) || ( c1 == '[' && c2 == ']' ) || ( c1 == '{' && c2 == '}' ));
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// code your solution here
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private static boolean checkNextChar( Deque<Integer> stack, Iterator<Integer> iter ) {
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if ( ! iter.hasNext() ) return stack.isEmpty();
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int c = iter.next();
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if ( BRACKETS_MATCH.test( stack.peek(), c )) {
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stack.pop();
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}
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else {
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stack.push( c );
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}
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return checkNextChar( stack, iter );
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}
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public static void main( String[] args ) {
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// hint: read values via Scanner methods
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var inputLine = new Scanner( System.in ).nextLine();
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var stack = new ArrayDeque<Integer>( inputLine.length() );
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var iter = inputLine.chars().iterator();
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// Write result with System.out.println()
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System.out.println( checkNextChar( stack, iter ) );
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}
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}
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